Question

A crate is dragged up a ramp at constant speed. The work done on the system can be accounted for by:

- Eel
-Eg
-Ek
-Eint
-both Eg and Eint

Answer 1

The work done on the system can be accounted for by;

Both
`E_g` and
`E_(int)`

Step-by-step explanation:

The speed of the crate = Constant

Therefore, the acceleration of the crate = 0 m/s²

The net force applied to the crate,
`F_(NET)` = 0

Therefore, the force of with which the crate is pulled = The force resisting the upward motion of the crate

However, we have;

The force resisting the upward motion of the crate = The weight of the crate + The frictional resistance of the ramp due to the surface contact between the ramp and the crate

The work done on the system = The energy to balance the resisting force = The weight of the crate × The height the crate is raised + The heat generated as internal energy to the system

The weight of the crate × The height the crate is raised = Gravitational Potential Energy =
`E_g`

The heat generated as internal energy to the system =
`E_(int)`

Therefore;

The work done on the system =
`E_g` +
`E_(int)`.