Question

I have a triangle that has an area of 27 square feet. And the height is three times the length of the base. How do I find the height and base of the triangle?

Answer 1

Area = 1/2 x base x height; but height = 3 x base

Area = 1/2 x base x 3 x base = 3/2 b^2
27 = 3/2 b^2
b^2 = (2 x 27)/3 = 18

`base=√(18)=3√(2)` and
`height=3(3√(2)) = 9√(2)`