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The area of a square is numerically 45 more than the perimeter. find the length of the side

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Area of square = l²
Perimeter of square = 4l

According to the question,

l^2 = 45 + 4l \\\\ l^2 - 4l - 45 = 0 \\\\ l^2 -9l+5l-45=0 \\\\ l(l-9)+5(l-9) =0 \\\\(l-9)(l+5)=0

Using zero product property,

Either,

l-9 = 0 \\ ~~~~~~l = 9

Or,

l+5=0 \\ ~~~~~~l=-5

Since length can't be negative, the length is 9


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