Question

How many grams of calcium nitrate are needed to react completely with 2.00 moles of hydrochloric acid?

Answer 1

We are required to calculate mass of calcium nitrate, given the following balanced equation:

`\text{Ca(NO}_3)_2\text{ + }2\text{HCl}\rightarrow CaCl_2\text{ + }2HNO_3`

Given:

moles of HCl = 2 mol

We can use the stoichiometry to calculate the moles of Ca(NO3)2.

The molar ratio between HCl and Ca(NO3)2 is 1:2

Therefore the number of moles of Ca(NO3)2 = 2 x (1/2) = 1.00 mol

Now that we do have the number of moles we can calculate the mass.

n = m/M

m = n x M

m = 1.00 x 164.09

m = 164 g

Therefore the answer is the last one.