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5 votes
Solve 5|x-3|-8≥2 and give the final answers that would make the equation true

User Mermoz
by
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1 Answer

3 votes
ok so oadd 8 to both sides

5|x-3|≥10
divide both sides by 5
|x-3|≥2

now assume negative and positive and don't forget to flip sign
x-3≥2 and x-3≤-2

x-3≥2
add 3
x≥5

x-3≤-2
add 3
x≤1

x≤1 and x≥5
User TiLithitum
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8.6k points