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22 votes
22 votes
What is the probability of P(A)=1/2 , P(B|A) = 63/100 , P (A n B) = ?

User Maxpenguin
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1 Answer

19 votes
19 votes

The conditional probability formula states that given events A and B,


P(A|B)=(P(A\cap B))/(P(B))

Therefore, in our case,


\begin{gathered} P(B|A)=(P(A\cap B))/(P(A)) \\ \Rightarrow P(A\cap B)=P(B|A)*P(A)=(63)/(100)*(1)/(2)=(63)/(200) \end{gathered}

Thus, the answer is 63/200=0.315

User Tareq Albeesh
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