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41 votes
7. If a circuit has L closed loops, B branches, and J junctions the number of independent loopequations is:A. B − J + 1B. B − JC. BD. LE. L − J

User Kosa
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1 Answer

16 votes
16 votes

Given:

Number of closed loops = L

Number of branches = B

Number of junctions = J

Let's determine the number of independent loop equation.

In a circuit, to write the equation which represents the number of independent loop, apply the Fundamental Theorem in Network Topology.

Since the circuit has L closed loops, B branches and J junctions, we have the equation:


B=L+J-1

Now, for the number of independent loop rewrite the equation for L:


L=B-J+1

Therefore, the number if independent loop equation is:


L=B-J+1

ANSWER: A


B-J+1

User Oam
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