Register

There are two natural numbers. one exceeds the other by 40. if the ratio of the two numbers is 7 : 3, find the numbers.

There are two natural numbers. one exceeds the other by 40. if the ratio of the two numbers is 7 : 3, find the numbers.
185k views
4 votes
there are two natural numbers. one exceeds the other by 40. if the ratio of the two numbers is 7 : 3, find the numbers.

User Fiacc
by
7.9k points

1 Answer

5 votes
Let the two numbers be x and x + 40, then
7/3 = (x + 40)/x
7x = 3(x + 40) = 3x + 120
7x - 3x = 120
4x = 120
x = 120/4 = 30

Therefore, the two numbers are 30 and 70.
User Nyks
by
7.8k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Link Copied!