Question

Two capacitors of values of 10 μF and 20 μF are connected in parallel, and in turn, are connected in series with a 30 μF capacitor. Find the equivalent capacitance of this arrangement.Group of answer choices15 μF12 μF10 μF7 μF

Answer 1

15 μF

Step-by-step explanation:

If two capacitors are in parallel, the equivalent capacitance is equal to the sum of the capacitances, so for the first two capacitors, we get:

C = 10 μF + 20 μF

C = 30 μF

Then, this capacitor C is in series with another capacitor of 30μF. For capacitor in series, we can find the equivalent as follows

`\begin{gathered} (1)/(C_(eq))=(1)/(30\mu F)+(1)/(30\mu F) \\ (1)/(C_(eq))=(1)/(15\mu F) \\ C_(eq)=15\mu F \end{gathered}`

Therefore, the answer is 15μF