First you find 2^2, AKA, 2 squared. We would have 4. Now we cube it. It becomes 4^3, which is 64. So that's the first one. The next one is 2 cubed, and then squared. So that will be 8. Then we do 8 squared. This gives us once again, 64. In the end, you can say that the two problems are the same. When there is an exponent on the inside and on the outside of the parentheses, you can simply add them together to have one over all number. Even though the numbers are reversed for both equations, they ultimately have the same outcome due to this.