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The first two terms of a geometric sequence are a1 = 1/3 and a2 = 1/6. What is a8, the eighth term? A. 1/384 B. 1/128 C. 1/768 D. 1/256
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The first two terms of a geometric sequence are a1 = 1/3 and a2 = 1/6. What is a8, the eighth term?

A. 1/384
B. 1/128
C. 1/768
D. 1/256

User Shane Oliver
by
7.9k points

1 Answer

4 votes
a1=1/3
a2 = 1/6
The constant factor is 1/2
a1=2/3*1/2
a2=2/3*1/2^2
So ...
a8=2/3*(1/2)^8
2/3*1/256
A. 1/384
User Mloughran
by
9.1k points
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