Question

A car, initially at rest, accelerates at 3.34 m/s2 for 12.1 s. How far did in go in this time?

Answer 1

Given:

The initial velocity of the car, u=0 m/s

The acceleration of the car, a=3.34 m/s²

The time interval, t=12.1 s

To find:

The distance covered by the car.

Step-by-step explanation:

From the equation of motion,

`d=ut+(1)/(2)at^2`

On substituting the known values,

`\begin{gathered} d=0+(1)/(2)*3.34*12.1^2 \\ =244.5\text{ m} \end{gathered}`

Final answer:

The distance covered by the car is 244.5 m