Question

Odina walked down the hall at school from the cafeteria to

the band room, a distance of 100.0 m. A class of physics
students recorded and graphed her position every 2.0 s,
noting that she moved 2.6 m every 2.0 s. When was Odina
in the following positions?
a. 25.0 m from the cafeteria
b. 25.0 m from the band room
c. Create a graph showing Odina’s motion.

Answer 1

I think no 1 not sure

Answer 2

Step-by-step explanation:

As we know that when graph is plotted with the position and time then it shows that it will move with uniform speed

So here it is moving 2.6 m in 2 s

so speed is given as

`v = (2.6)/(2)`

`v = 1.3 m/s`

Part a)

when she reach 25 m from cafeteria

time taken by her

`t = (d)/(v)`

`t = (25)/(1.3)`

`t = 19.2 s`

Part b)

When she will reach 25 m from band room

then total distance moved from cafeteria is

`d = 100 - 25 = 75m`

time taken by her

`t = (75)/(1.3)`

`t = 57.7 s`

Part c)

Since Odina is moving at constant speed

so the position time graph must be a straight line graph