Question

Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE=11x−3 and CE=12−4x. Find x.A. 18B. 8C. 1D. 16

Answer 1

Now, let us draw the diagram of the parallelogram

From the image above, E is the mid-point of the line AC.

This means that AE = CE. From here we have that

`11x-3=12-4x`

Now we can find x. This becomes

`\begin{gathered} 11x-3=12-4x \\ \\ 11x+4x=12+3 \\ \\ 15x=15 \\ \\ x=(15)/(15) \\ \\ x=1 \end{gathered}`

So, the correct answer is option C.