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7 votes
How would I find the area of a trapezoid whose bases are x and 3x+4 and height is x+2

User Ben Nieting
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1 Answer

15 votes
15 votes

Area of Trapezium.

By formula,


\begin{gathered} \text{Area =}(1)/(2)(a\text{ + b)h} \\ \text{Where a =x , b = 3x+4 , and h = x + 2} \\ \text{Area =}(1)/(2)(x+3x+4)(x+2) \\ \text{Area =}(1)/(2)(4x+4)(x+2) \\ \\ \text{Area = }(1)/(2)*4(x+1)(x+2)\text{ =2(x+1)(x+2)} \end{gathered}

So, the correct answer is 2(x+1)(x+2)

User Mind Peace
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