Question

At a constant pressure and a temperature of 280 K, the gas in a cylinder has a volume of 10.0 liters. If the volume of the gas is increased to 20.0 Liters what is the new temperature?

Answer 1

V1/T1=V2/T2 so T1/V1*V2= 280K/10l*20l=560K. Weird question, but this should be the answer

Answer 2

560K

Step-by-step explanation:

For the question above we apply Charles law.

Charles law states that at constant pressure, the Volume of an ideal gas is directly proportional to it's temperature in Kelvin(Absolute Temperature).

Charles law is represented mathematically by:

V₁/ T₁ = V₂/T₂

Where V₁= 10.0 liters , T₁ = 280K

V₂= 20.0 litres, T₂ = ?

Therefore, 10/280 = 20/T₂

Cross multiplying

10× T₂= 280×20

T₂= (280×20)÷ 10

T₂ = 560K

The new temperature is 560K.