Question

How many moles of MgS2O3 are in 185 g of the compound?

Answer 1

Molar mass MgS2O3 = 136.43 g/mol


185 g x 1 mole MgS2O3 / 136.43 => 1.356 moles

hope this helps!

Answer 2

Answer: The number of moles of
`MgS_2O_3` is 1.36 moles.

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

Given mass of
`MgS_2O_3` = 185 g

Molar mass of
`MgS_2O_3` = 136.43 g/mol

Putting values in above equation, we get:

`\text{Moles of }MgS_2O_3=(185g)/(136.43g/mol)=1.36mol`

Hence, the number of moles of
`MgS_2O_3` is 1.36 moles.