Question

Given that cos (x) = 1/3, find sin (90 - x)

Answer 1

A/c to trigonometric relations, sin(90 - x) = cos(x),
that means sin(90 - x) = cos(x) = 1/3.

Answer 2

`\sin(90^(\circ) - x)=(1)/(3)`

Explanation:

Given:
`\cos (x)=(1)/(3)`

We have to find the value of
`\sin(90^(\circ) - x)`

Since Given
`\cos (x)=(1)/(3)`

Using trigonometric identity,

`\sin(90^(\circ) - \theta)=\cos\theta`

Thus, for
`\sin(90^(\circ) - x)` comparing , we have,

`\theta=x`

We get,

`\sin(90^(\circ) - x)=\cos x=(1)/(3)`

Thus,
`\sin(90^(\circ) - x)=(1)/(3)`