Question

if 59.3 grams of potassium chlorate decomposes, how many grams of oxygen gas can be produced? 2 kclo3 → 2 kcl 3 o2

Answer 1

Molar mass :

KClO3 = 122.55 g/mol
O2 = 31.99 g/mol

2 kClO3 = 2 KCl + 3 O2

2 x 122.55 g -------- 3 x 31.99 g
59.3 g --------------- ?? ( mass of O2)

59.3 x 3 x 31.99 / 2 x 122.55 =

5691.021 / 245.1 => 23.21 g of O2

hope this helps!