Question

Objects A and B each have a mass of 25 kilograms. Object A has a velocity of 5.98 meters/second. Object B is stationary. They undergo a perfectly elastic collision in one dimension. What is the total kinetic energy of the system after the collision?

A.)1.2 x 10^2 J
B.)4.5 × 10^2 joules
C. 5.0 × 10^2 joules
D. 9.5 × 10^2 joules
E. 1.1 × 10^3 joules

Answer 1

There are numerous information's already given in the question. Based on those information's, the answer can be easily deduced.

Mass of the objects = 25 kg
Velocity of object A = 5.98 m/s
Velocity of object B = 0 m/s
Total kinetic energy = (1/2) * mass * (velocity)^2
= 0.5 * 25 * (5.98)^2
= 4.5 * 10^2 joules.
From the above deduction, we can conclude that the correct option among all the options that are given is option "B".

Answer 2

Answer;

= 4.5 * 10^2 joules.

Explanation;

• A perfectly elastic collision is a type of collision in which kinetic energy is conserved.

• Therefore, to calculate the kinetic energy of the system after the collision we use the formula 1/2 mv²

Mass = 25 kg

Velocity = 5.98 m/s

KE = 1/2 × 25 × 5.98 ²

= 447 Joules

This translates to about 4.5 ×10^2 Joules