Question

Solve by factoring
`y {}^(2) - 4y - 12 = 0`

Answer 1

`\begin{gathered} \text{ To solve }y^2-4y-12=0\text{ by factorization method} \\ \end{gathered}`
`\begin{gathered} y^2-4y-12=0\text{ } \\ =y^2-6y+2y-12=0 \\ =y(y-6)+2(y-6)=0 \\ (y-6)\text{ is a common factor} \\ =(y-6)(y+2)=0 \\ y-6=0\text{ and y+2=0} \\ y=6\text{ and y=-2} \end{gathered}`

The answer is y = 6 and y= -2