Question

10x-35+3ax=5ax-7a solve for "a" for which the equation is an identity.

Answer 1

10x - 35 +3ax=5ax-7a
10x-35=5ax-3ax-7a
10x-35=a(2x-7)===> a= (2x-7)/(10x-35)

Answer 2

10x - 35 + 3ax = 5ax - 7a Subtract 3ax from both sides
10x - 35 = 2ax - 7a Factor a out of the right side
10x - 35 = a (2x - 7) Divide both sides by (2x - 7)

`(10x - 35)/(2x - 7)` = a Switch the sides to make it easier to read
a =
`(10x - 35)/(2x - 7)`