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X^2+10x-6=0.........
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X^2+10x-6=0.........

User Ihar Katkavets
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puting it into the quadrait equation ((-b+-[b^2-4ac]^(1/2)/2a), we get that x= 31^(1/2)-5 or 31^(1/2)+5
User Quadroid
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