Question

What is the product of (2p + 7)(3p2 + 4p – 3)?

Answer 1

(2p + 7)(3p^2 + 4p - 3) = 2p(3p^2 + 4p - 3) + 7(3p^2 + 4p - 3) =
6p^3 + 8p^2 - 6p + 21p^2 + 28p - 21 =
6p^3 + 29p^2 + 22p - 21 <===

Answer 2

`6p^(3) +29p^(2) +22p-21`

Explanation:

This is a polynomial product where we have to apply distributive property and exponent properties (image is attached).

So, applying distributive property:

`(2p + 7)(3p^(2)  + 4p-3)\\6p^(3)+8p^(2)-6p+21p^(2)+28p-21`

Then, we reduce like terms:

`6p^(3) +29p^(2) +22p-21`

Therefore, the product is

`6p^(3) +29p^(2) +22p-21`