Question

The chemical equation below shows the decomposition of nitrogen triiodide (NI3) into nitrogen (N2) and iodine (I2).

2NI3 -> N2 + 3I2

The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I 2 will form 3.58 g of NI3?

A). 0.00907
B). 0.00940
C). 0.0136
D). 0.0212

Answer 1

Answer is C on Edge

Step-by-step explanation:

Answer 2

2 NI₃= N₂ + 3 I₂

2 x 394.71 g --------------- 3 x 253.80 g
3.58 g ---------------------- ( mass of I₂ )

3.58 x 3 x 253.80 / 2 x 394.71 =

2725.812 / 789.42 => 3.4529 g of I₂

1 mole I₂ --------------- 253.80 g
?? ----------------------- 3.4529 g

3.4529 x 1 / 253.80 => 0.0136 moles of I₂

Answer C

hope this helps!