Question

Identify the limiting reactant when 6.33 g of H2SO4 reacts with 5.92 g of NaOH to produce Na2SO4 and water.

Answer 1

H₂SO₄:

m=6.33g
M=98g/mol

n = m/M = 6.33g/98g/mol ≈ 0,065mol

NaOH:

m=5.29g
M=40g/mol

n = m/M = 5.29g/40g/mol ≈ 0,132mol

2NaOH + H₂SO₄ ⇒ Na₂SO₄ + 2H₂O
2mol : 1mol : 1mol
0.132mol : 0.065mol : 0.065mol
too much limiting
reactant

Limiting reactant is H₂SO₄.