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Find the exact real value of arccos(-sqrt(2)/2).
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Find the exact real value of arccos(-sqrt(2)/2).

User Iusting
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2 Answers

1 vote

Answer: -1

Step-by-step explanation: pre cal ED

User Heroxav
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arccos(-sqrt(2)/2). range of cos − 1 ( x )=[ 0 , π ]
= arccos(0.706 )
=45 degrees
hope this helps
User Austin Wood
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