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Solve, using the substitution method. y – 2x = 8 16 + 4x = 2y a. The solution is (24, 0). b. The solution is (1, 10). c. There is no solution. d. There are an infinite number of…

Solve, using the substitution method. y – 2x = 8 16 + 4x = 2y a. The solution is (24, 0). b. The solution is (1, 10). c. There is no solution. d. There are an infinite number of…
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Solve, using the substitution method.

y – 2x = 8
16 + 4x = 2y

a. The solution is (24, 0).
b. The solution is (1, 10).
c. There is no solution.
d. There are an infinite number of solutions.

User Muirbot
by
9.5k points

1 Answer

4 votes
y - 2x = 8 . . . . (1)
16 + 4x = 2y . . (2)

From (1), y = 2x + 8 . . . (3)

Putting (3) into (2) gives
16 + 4x = 2(2x + 8) = 4x + 16
0 = 0

Therefore, there are infinite number of solutions.
User Wongx
by
8.8k points
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