Question

Geometry***please help me find the surface area and volume of this figure

Answer 1

`\begin{gathered} \text{Volume 1} \\ \text{ V = }\pir^2h \\ \text{ V = 3.14(4)}^2(6) \\ \text{ V = 301.44 in}^2 \\ \text{Volume 2} \\ V\text{ = }\pi(1)^2(6) \\ V\text{ = 18.84} \end{gathered}`

Final volume = 301.44 - 18.84

Final volume = 282.6 in^2 This is the result

Perimeter = 2(3.14)(4)

Perimeter = 25.12 in

Perimeter 2 = 2(3.14)(1)

Perimeter 2 = 6.28

Area 1 = 6 x 25.12

Area 1 = 150.72 in ^2

Area 2 = 6 x 6.28

Area 2 = 37.68 in^2

Final area = 150.72 - 37-68

= 113.04 in