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What is the series in sigma notation? -5 + (-1) + 3 + 7 + 11?
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5 votes
What is the series in sigma notation? -5 + (-1) + 3 + 7 + 11?

User Electrino
by
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2 Answers

5 votes

Answer:

5

∑(4j-9)

J=1

Explanation:

User Jagadeesh J
by
8.5k points
2 votes
For the series:
- 5 + ( - 1 ) + 3 + 7 + 11
common difference between the numbers is 4 and a 1 = -5
The series in sigma notation:
4
∑ ( 4 i - 5 )
i =0
User Simaglei
by
8.8k points
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