Question

Greyhound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but

3 leaps of the hound are equal to 5 leaps of the hare. Compare the speed of the
hound and the hare,

need full solution:-​

Answer 1

`{\large{\bold{\rm{\underline{Given \; that}}}}}`

★ A grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.

`{\large{\bold{\rm{\underline{To\; find}}}}}`

★ The speed of the hound and the hare

`{\large{\bold{\rm{\underline{Solution}}}}}`

★ The speed of the hound and the hare = 25:18

`{\large{\bold{\rm{\underline{Full \; Solution}}}}}`

`\dashrightarrow` As it's given that a grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.

So firstly let us assume a metres as the distance covered by the hare in one leap.

Ok now let's talk about 5 leaps,.! As it's cleared that the hare cover the distance of 5a metres.

But 3 leaps of the hound are equal to 5 leaps of the hare.

Henceforth, (5/3)a meters is the distance that is covered by the hound.

Now according to the question,

Hound pursues a hare and takes 5 leaps for every 6 leaps of the hare..! (Same interval)

Now the distance travelled by the hound in it's 5 leaps..!

• (5/3)a × 5

• 25/3a metres

Now the distance travelled by the hare in it's 6 leaps..!

• 6a metres

Now let us compare the speed of the hound and the hare. Let us calculate them in the form of ratio..!

• 25/3a = 6a

• 25/3 = 6

• 25:18