Question

I have to graph the equation y= - 2/3 x + 1 and I dont remember how. can you help

Answer 1

Given the equation:

`\text{ y = -}(2)/(3)x\text{ + 1}`

To be able to graph the equation, let's identify at least two points that pass through the graph of the equation. We can get this by getting them at two conditions: when x = 0 and y = 0.

At x = 0:

`\text{ y = -}(2)/(3)x\text{ + 1}`
`\text{ y = -}(2)/(3)(0)\text{ + 1}`
`\text{ y = 1}`

Therefore, Point A: (0,1) = x1,y1.

At y = 0:

`\text{ y = -}(2)/(3)x\text{ + 1}`
`\text{0 = -}(2)/(3)x\text{ + 1}`
`(2)/(3)x\text{ = 1}`
`\text{ x = (}(3)/(2))(1)\text{ = }(3)/(2)`

Therefore, Point B: (3/2,0) = x2,y2.

Let's now plot the graph of the equation.