Question

The quadratic equation $y = x^2 + 5x + c$ has solutions in the form of $x = \frac{-5 \pm \sqrt{c}}{2}$. What is the value of $c$?

Answer 1

`ax^2+bx+c=0\\\\x_1=(-b-√(\Delta))/(2a)\ and\ x_2=(-b+√(\Delta))/(2a)\\\\\Delta=b^2-4ac`


`y=x^2+5x+c\\\\a=1;\ b=5;\ c=c\\\\x=(-5\pm\sqrt\Delta)/(2\cdot1)\\\\\Delta=5^2-4\cdot1\cdot c=25-4c\\\\Therefore:x=(-5\pm√(25-4c))/(2)`