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If 268.5 grams of Aluminum sulfide reacts with excess water at STP, how many liters of Hydrogen sulfide gas is produced?
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If 268.5 grams of Aluminum sulfide reacts with excess water at STP, how many liters of Hydrogen sulfide gas is produced?

User Omri Luzon
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1 Answer

7 votes
2Al + 6H₂O ⇒ 2Al(OH)₃ + 3H₂
2mol : 2V
54g : 67,2L
268,5g : Vₓ

vₓ = 67,2dm³*268,5g / 54g ≈ 334,13L
User Pedryk
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