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Can someone help me Using the trigonometric ratios, solve for the missing sides x and y of each right triangle. Round your answers to the nearest tenth.

Can someone help me Using the trigonometric ratios, solve for the missing sides x-example-1
User Cena
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1 Answer

13 votes
13 votes

Given,

The measue of one side is 19.

The measure of one angle is 80 degree.

Required

The value of x and y.

a)By trigonometric ratio,


\begin{gathered} sin80^(\circ)=(19)/(x) \\ x=(19)/(sin80^(\circ)) \\ x=19.3 \end{gathered}

The value of y is calculatedby using cosine,


\begin{gathered} cos80^(\circ)=(y)/(19.29) \\ y=cos80^(\circ)*19.29 \\ y=3.4 \end{gathered}

Hence, the value of x is 19.3 and y is 3.4.

b)By trigonometric ratio,


\begin{gathered} sin45^(\circ)=(y)/(27) \\ y=sin45^(\circ)*27 \\ y=19.1 \end{gathered}

The value of x is calculatedby using cosine,


\begin{gathered} cos45^(\circ)=(x)/(27) \\ x=cos45^(\circ)*27 \\ x=19.1 \end{gathered}

Hence, the value of x is 19.1 and y is 19.1.

User Aforankur
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