Question

A sandbox has an area of 26 square feet, and the length is 5-1/2 feet. What is the width of the sandbox?

Answer 1

(5 1/2) x width = 26;
Then, (11/2) x width = 26;
width = 26 ÷ (11/2);
width = (26x2)/11;
width = 52/11 = 4.72 feet;

Answer 2

Width of the sandbox, b = 4.72 feet

Explanation:

It is given that,

The area of the sandbox,
`A=26\ ft^2`

Length of the box,
`l=5(1)/(2)\ ft=5.5\ ft`

We need to find the width of the sandbox. The area of the rectangle is given by :

`A=l* b`

b is the width of the sandbox

So,
`b=(A)/(l)`

`b=(26)/(5.5)`

b = 4.72 feet

So, the width of the sandbox is 4.72 feet. Hence, this is the required solution.