Question

what is the equation in slope-intercept form, of the line prependicular to y= -3/5x +6 that passes through the point with coordinants (12,25)

Answer 1

y=5/3x+5

Explanation:

change slope in equation given to the negative reciprocal since the line is perpendicular:

-3/5 to 5/3

put values into point slope form y-y1=m(x-x1)

y1 = y in the point given, which is 25

m = slope, which is 5/3

x1 = x in point given, which is 12

y-25=5/3(x-12)

then solve for slope intercept form y=mx+b to get

y=5/3x+5