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How many grams are in 3.1 x 10^11 atoms of chlorine

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6,02*10^(23) \ \ \ \ \ \rightarrow \ \ \ 35,5g\\ 3,1*10^(11) \ \ \ \ \ \ \rightarrow \ \ \ x\\\\ x=(3,1*10^(11)*35,5g)/(6,02*10^(23))\approx 18,3*10^(-2)g=0,183g
User Adrian Guerrero
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