Question

Calculate the specific heat (J/g∘C) for a 18.5-g sample of tin that absorbs 183 J when temperature increases from 35.0 ∘C to 78.6 ∘C.

Answer 1

`Q=cm \Delta T \ \ \ \ \ \Rightarrow \ \ \ c=(Q)/(m\Delta T)\\\\ Q=183J\\ m=18,5g\\ \Delta T=78,6^(o)C-35^(o)C=43,6^(o)C\\\\ c=(183J)/(18,5g*43,6^(o)C)\approx0,227(J)/(g^(o)C)`

Answer 2

0.227 J/g°C

Step-by-step explanation:

Specific heat is the heat change by one gram of substance if it is subjected to change of 1 degree celsius.

The relation between specific heat and mass and change in temperature is:

Q = heat change = mass X specific heat X change in temperature.

Given:

Q = 183 J

Mass = 18.5g

increase in temperature = 78.6-35 = 43.6 °C

Putting values

183 = 18.5X specific heat X 43.6

Specific heat =
`(183)/(18.5X43.6)= 0.227`
`(J)/(g^(0)C)`