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MnO2 + 4HCl reacts to form MnCl2 + CL2 + 2H2O If .86 mol of MnO2 and 48.2 g of HCl react, which reactant is the limiting reagent
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Jul 13, 2017
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MnO2 + 4HCl reacts to form MnCl2 + CL2 + 2H2O If .86 mol of MnO2 and 48.2 g of HCl react, which reactant is the limiting reagent
Chemistry
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Leonardo Kuffo
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HCl:
m=48,2g
M=36,5g/mol
n = m/M = 48,2g / 36,5g/mol = 1,32mol
1mol : 4mol
MnO₂ + 4HCl ⇒ MnCl₂ + Cl₂ + 2H₂O
0,86mol : 1,32mol
limiting reagent
0,33 will react
HCl is limiting reagent.
CreativePS
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Jul 18, 2017
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