Question

A common resistance of carbon resistors is 33 ΩΩ. How many 33 ΩΩ resistor, connected in parallel, are needed to give a total resistance of 5.5 ΩΩ?

Answer 1

Let n be the required number of 33 ohm resistors.

`n*((1)/(33))=(1)/(5.)`

`n=(33)/(5.5)=6`
The required number of 33 ohm resistors in parallel is 6 resistors.

Answer 2

6 resistors.

Explanation:

Common resistance of carbon resistors has been given as 3 Ω

When resistors added in parallel connection total resistance is given by the expression

`(1)/(R)` =
`(1)/(R_1)` +
`(1)/(R_2)`...........
`(1)/(R_n)`

If n resistors have been added then
`(1)/(R)` =
`(n)/(r)`

here r = 3Ω and R = (0.5)Ω

`(n)/(3)`=
`(1)/(0.5)`

n =
`(3)/(0.5)` = 6 resistors.