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What is an equation for a line with the slope 3/2 that passes through the point (-2,0)

User MLyck
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1 Answer

3 votes
y=3/2X+3

y=mx+b
3/2 = slope (m)
y-y1=m(X-X1)
(-2 = X1)
(0 = Y1)

y-0=3/2(x-(-2)
y=3/2x+3

User Lazytype
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