Question

The length of a rectangle is 3 units shorter than one-third of the width, x. Enter an expression in the box that represents the perimeter of the rectangle. Note: Use one variable and a fraction in the answer.

Help please! I have absolutely no idea how to solve!!!! ^^^

Answer 1

Since length is 3 less than 1/3 width, set up equation l=(1/3)w-3. Because P=2(l+w), substitute l with the euation and get P=2(4/3w-3)

Answer 2

Let

y----------> the length side of the rectangle

x-----------> the width side of the rectangle

we know that

the perimeter of the rectangle is equal to

`P=2x+2y` --------> equation
`1`

`y=(x)/(3)-3` --------> equation
`2`

substitute equation
`2` in equation
`1`

`P=2x+2[(x)/(3)-3]\\ \\P=2x+ (2x)/(3)-6 \\ \\P=((8x)/(3)-6)\ units`

therefore

the answer is

`P=((8x)/(3)-6)\ units`