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2Ca3(PO4)2 + 6SiO2 + 10C --> P4 + 6CaSiO3 + 10CO how many grams of calcium phosphate are required to give 30.0g of phosphorus?? I got 542g but I think that is way off. I did 30g P/30.97g to get .989 moles P • 2Ca= 1.94 mole Ca• 279.21g to get from miles to grams. Please explain how to do it and if you can where I went wrong.

1 Answer

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2mol : 1mol
2Ca₃(PO)+ 6SiO + 10C P + 6CaSiO + 10CO
620g : 124g
x : 30g


x=(30g*620g)/(124g)=150g


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