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How to differentiate
f(x)= (5)/(x) +1

find f'(x) and f'(2) and f'(4)
I know that to differentiate you do

\lim_(changex \to 0) (f(x+changex)-f(x))/(changex) where changex=Δx
but I'm stuck
ples help

1 Answer

5 votes

f(x) = (5)/(x) =5x^-^1


f'(x)= -5x^-^2= (-5)/(x^2)


\text{plug in x = 2 and x=4}


f'(2)= (-5)/(2^2) = 2^2 = 4 = (-5)/(4)


f'(4)= (-5)/(4^2) = 4^2 = 4*4 = 16 = (-5)/(16)


\text{Hence solved }
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