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Calculate the frequency required to eject electrons from gold with a work function of 8.76 x 10-19 J

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hf=W+(mv^(2))/(2)\\\\ f=(W+(mv^(2))/(2))/(h)\\\\\ W=8,76*10^(-19)J\\ m=9,11*10^(-31)kg\\ v=3*10^(8)(m)/(s)\\ h=6,63*10^(-34)Js\\\\\\ f=(8,76*10^(-19)J+(9,11*10^(-31)kg*(3*10^(8)(m)/(s))^(2))/(2))/(6,63*10^(-34)Js)=7,5*10^(19)Hz
User Bogdan Burym
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