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a pilot can withstand an acceleration of up to 9g, which is about 88 m/s2, before blacking out. (a) what is the acceleration experienced by a pilot flying in a circle of constant radius at a constant speed of 485 m/s if the radius of the circle is 2140 m? (b) does the pilot make the turn without blacking out?

User Kaleissin
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2 Answers

4 votes

Answer

a) 109.918 m/s²

b) No

Step-by-step explanation

a)

The angular acceleration a= ω²r = v²/r.

Where v is tangential velocity and r is the radius.

a = v²/r.

= 485² ÷ 2140

= 235,225/2140

= 109.918 m/s²

b) No

The critical acceleration 88 m/s². This is the maximum acceleration the pilot can withstand before blacking out.

The acceleration 109.918 m/s² is greater than the maximum acceleration, so the pilot will black out before making a turn.

User Edwin Iskandar
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8.4k points
1 vote
(a) what is the acceleration experienced by a pilot flying in a circle of constant radius at a constant speed of 485 m/s if the radius of the circle is 2140 m?
We calculate as follows:

Acceleration = (v^2)/r = 485^2 / 2140 = 110 m/s^2

(b) does the pilot make the turn without blacking out?

I think no, the pilot does not make the turn without blacking out.
User JustDanyul
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