Question

What volume of 0.46M NaOH is required to neutralize 50.0 mL of 0.31 M OF of HNO3

Answer 1

33.7 mL of NaOH

Step-by-step explanation

Given:

Molarity of NaOH = 0.46 M

Molarity of HNO3 = 0.31 M

Volume of HNO3 = 50.0 mL

What to find:

The volume of NaOH.

Step-by-step solution:

The equation for the reaction is:

NaOH + HNO3 → NaNO3 + H2O

Mole ratio of NaOH to HNO3 is 1:1

The volume of NaOH can be calculated using:

`\begin{gathered} (C_aV_a)/(n_a)=(C_bV_b)/(n_b) \\ \\ (0.31M*50.0mL)/(1)=(0.46M* V_b)/(1) \\ \\ V_b=(0.31M*50.0mL)/(0.46M) \\ \\ V_b=33.7\text{ }mL \end{gathered}`

Hence, 33.7 mL of 0.46M NaOH is required to neutralize 50.0 mL of 0.31 M OF of HNO3