Question

What is the molality of a solution that contains 109 grams of NaOH dissolved in 4.55kg of water? The molar mass of NaOH is 40.00

Answer 1

`C_(m)=(n)/(V)=(m_(s))/(MV)\\\\ d=(m)/(V) \ \ \ \Rightarrow \ \ \ V=(m)/(d)=(4550g)/(1(g)/(cm^(3)))=4550cm^(3)=4,55L\\\\ C_(m)=(109g)/(40(g)/(mol)*4,55L)\approx0,6M`