Calculate the amount of heat required to heat a 1.5 kg gold bar from 21°C to 68°C

asked Apr 2, 2017 98.8k views

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$Q=mc\Delta T\\\\ m=1,5kg=1500g\\ c_(Au)=0,129(J)/(g^(o)C)\\ \Delta T=68-21=47^(o)C\\\\ Q=1500g*0,129(J)/(g^(o)C)*47^(o)C=9094,5J$

James Burton answered Apr 9, 2017

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